How many numbers in the following list of 15 numbers are even:
1 , 1 0 , 1 1 , 1 0 0 , 1 0 1 , 1 1 0 , 1 1 1 , 1 0 0 0 , 1 0 0 1 , 1 0 1 0 , 1 0 1 1 , 1 1 0 0 , 1 1 0 1 , 1 1 1 0 , 1 1 1 1 ?
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read question carefully...
10,100,110,1000,1010,1100,1110 so even number=7
why?
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Maybe because they are all binary. 1 = 1 , 1 0 = 2 , 1 1 = 3 , 1 0 0 = 4 , 1 0 1 = 5 , 1 1 0 = 6 , 1 1 1 = 7 , 1 0 0 0 = 8 , 1 0 0 1 = 9 , 1 0 1 0 = 1 0 , 1 0 1 1 = 1 1 , 1 1 0 0 = 1 2 , 1 1 0 1 = 1 3 , 1 1 1 0 = 1 4 , 1 1 1 1 = 1 5 . And the numbers of the list's number are 15, and the numbers of odd numbers in the list are 8, so 1 5 − 8 = 7 . is the answer.
all the number in the list divisible by 2 are even
whose last digit is 1, those are odd.. so there are 7 digits whose last digit is 0..
even numbers are the ones which end with the multiples of 2 but not with one and zero is a multiple of 2 there fore all numbers up there ending with 0 are even and there are total 7 numbers which end with zero answer= 7
charactristic even number is the last digit is even too. there are 7 numbers that satisfy
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The Numbers ending in 0 or even number are what I consider