even or odd

we know that :

$a^{n}-b^{n}=\left( a-b\right) \left( a^{n-1}+a^{n-2}b+a^{n-3}b^{2}+.\ldots ..+a^{2}b^{n-3}+ab^{n-2}+b^{n-1}\right)$

let $y$ equals the numerator $y=\left( 11^{4}\right) ^{25}-\left( 7^{4}\right) ^{25}=\left( 11^{4}-7^{4}\right) \left[ \left( 11^{4}\right) ^{24}+\left( 11^{4}\right) ^{23}\left( 7^{4}\right) +\ldots ..+\left( 11^{4}\right) \left( 7^{4}\right) ^{23}+\left( 7^{4}\right) ^{24}\right]$

so $x=\left[ \left( 11^{4}\right) ^{24}+\left( 11^{4}\right) ^{23}\left( 7^{4}\right) +\ldots ..+\left( 11^{4}\right) \left( 7^{4}\right) ^{23}+\left( 7^{4}\right) ^{24}\right]$

we know that $x$ is the sum of $25$ odd number, so $x$ is an $odd$ $number$