Within a square, suppose that every third of its perimeter is connected to form a triangle. Let be the ratio of the area of the triangle to the square. If the difference of the maximum and minimum value of can be expressed in the form , where and are coprime positive integers, determine the value of
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Using a graph, you can get the ratio of minimum area as 5/12 and the max as 4/9. The difference being 1/36, we get a=1;b=36.
So, 3 x (a+b) = 111.