How many integer solution does the equation below has?
6 x + 5 1 y = 1 6 9
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gcd(6,51)=3, which doesn't divide 169, so there are no integer solutions to this equation.
6 x + 5 1 y = 1 6 9 , therefore 2 x + 1 7 y = 3 1 6 9 .
So all real solutions will not be integer.
There is a typo on your RHS 3 1 6 9
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We observe that 51×4>169 this implies our y must be less than or equal to 3.We then do a trial as follows ,169-(51×3),169-(51×2),169-(51×1) and since non of the answers is divisible by 6,we conclude no answer.