Exclude

Algebra Level 3

Is there a number a 1 a 2 a 2 n 1 a 2 n \overline {a_1a_2 \cdots a_{2n-1}a_{2n}} ( n Z + n \in \mathbb Z_+ ) other than 9 9 n - 1 digits 8 0 0 n - 1 digits 1 \underbrace{9\cdots9}_{\text{n - 1 digits}}8\overbrace{0\cdots0}^{\text{n - 1 digits}}1 such that the following equation is sastified?

a 1 a 2 a 2 n 1 a 2 n = ( a 1 a n + a n + 1 a 2 n ) 2 \large \overline {a_1a_2 \cdots a_{2n-1}a_{2n}} = (\overline{a_1 \cdots a_n} + \overline{a_{n+1} \cdots a_{2n}})^2

Yes, there is. It depends on the value of n n . No, there is not.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...