Execution truth or lies
a man goes to execute a criminal. he takes three drinks, puts poison in two of them, then labels them as following:
a: i have poison
b: i don't have poison
c: glass b does not have poison
the man then gives the drinks to the criminal, then tells him that two of the labels are lying, and one is telling the truth. he also says that if the criminal drinks the glass without poison, his life will be spared and will be released from prison. which glass should the criminal choose to stay alive?
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1 solution
Glass B and C are either they're both lying or both telling the truth. The problem tells us that only ONE is telling the truth. So B and C must both be lying, meaning that there IS poison in glass B. Since glass A is telling the truth that it has poison, glass C will free the criminal.