Exp = log

Calculus Level 5

Let f ( b ) f(b) denote the number of real solutions x x satisfying b x = log b x . b^x = \log_b x.

Find the closed form of the integral 0 f ( b ) d b \displaystyle \int_0^\infty f(b) \, db to 3 decimal places.


The answer is 2.021311794.

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1 solution

Jeremy Galvagni
Apr 22, 2018

There are 3 3 solutions on ( 0 , e e ) (0,e^{-e})

There is 1 1 solution on [ e e , 1 ] [e^{-e},1]

There are 2 2 solutions on ( 1 , e 1 / e ) (1,e^{1/e})

There is 1 1 solution at e 1 / e e^{1/e}

There are 0 0 solutions on ( e 1 / e , ) (e^{1/e},\infty)

The integral then is just the areas of a few rectangles:

3 e e + 1 ( 1 e e ) + 2 ( e 1 / e 1 ) = 2 e e + 2 e 1 / e 1 = 2.021311794 3*e^{-e} + 1*(1-e^{-e}) + 2*(e^{1/e}-1) = 2e^{-e}+2e^{1/e}-1 = 2.021311794

Why are there 3 solutions in 0 to e^-e?

Aditya Gupta - 2 years, 8 months ago

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Jeremy Galvagni - 2 years, 8 months ago

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