Expansion of algebraic expression
(x-a)(x-b)=x^2-bx-ax+ab AND
(x-a)(x-b)(x-c)= -abc+abx+acx-ax^2+bcx-bx^2-cx^2+x^3
Thus, (x-a)(x-b)(x-c)........(x-y)(x-z)=?
Hint: If you are clueless, make use of term by term expansion and through hard work, you will find the correct answer.
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1 solution
0.
Note that there is a term,(x-x), in the expression that is the equivalent of zero.
Thus, no matter what we multiply zero by, we will still get zero.