Out of 4000 families with 5 children each, how many families would you expect to have at least 1 boy?
Note: Assume that the probability of a male birth is 2 1 .
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We could also calculate the complement, i.e., the number of families with no boys, and then subtract this value from 4000. The probability of there being no boys is ( 1 / 2 ) 5 = 1 / 3 2 , which represents ( 1 / 3 2 ) × 4 0 0 0 = 1 2 5 families, and thus we would expect there to be 4 0 0 0 − 1 2 5 = 3 8 7 5 families with at least one boy.
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You should put that in as a solution so that others can see it more easily. (That's how I did it too)
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The probability that a family has at least one boy is the complement of the probability that a family includes no boys. The probability that a family has no boys is ( 1 / 2 ) 5 = 1 / 3 2 , so the probability that a family has at least one boy is 1 − ( 1 / 3 2 ) = 3 1 / 3 2 , and so out of 4 0 0 0 families we would expect ( 3 1 / 3 2 ) × 4 0 0 0 = 3 8 7 5 families to have at least one boy.