Start by choosing two random natural numbers. Make a Fibonacci sequence starting with those two numbers. In other words, and are the two numbers you chose, and for , . What is the expected percentage of even numbers in the sequence? For clarification, I mean .
Write your answer as a decimal rounded to the nearest thousandth.
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You have a 4 1 chance for each of the following initial combinations:
For the first one, all elements of the series are even.
However, for the other three you end up with the sequence:
...EOOEOOEOOEOOEOOE...
with exactly 1/3 of the numbers being even.
So, the expected percentage is:
E = 4 1 + 3 1 + 3 1 + 3 1 = 0 . 5 = 5 0 %