Exponent challenge 6561

Using the fact that if the digital sum of an integer is divisible by 9, the integer is divisible by 9 to factorize $6561^{37}$ as follows:

$\begin{aligned} 6561^{37} & = (3^2\times 729)^{37} \\ & = (3^4\times 81)^{37} \\ & = 3^{8\times 37} \\ & = 3^{296} \\ & > 3^{287} \end{aligned}$

Therefore, $\boxed{6561^{37}}$ is greater .