Exponent Laws Problem

$\begin{aligned} 3^x & = (3^2)^6 \times (3^4 \div 3^2) \\ & = 3^{2\times 6}3^43^{-2} \\ & = 3^{12+4-2} \\ & = 3^{14} \\ \implies x & = \boxed{14} \end{aligned}$

$2\times6+4-2=14$

Due to exponent laws, $(3^2)^6 × (3^4÷3^2)$ is the same as $3^{2×6}×3^{4-2}$ which equals $3^{12+2}$ which equals $3^{14}$

Therefore, $x$ is 14.

Using a calculator it is obvious that the answer is 14

$\text{(3}^{2})^{6}=$ $\text{3}^{2×6}=$ $\text{3}^{12}$ .

$\frac{{3}^{4}}{{3}^{2}}={\text{3}^{4-2}}={\text{3}^{2}}$ .

Now , $\text{3}^{12}×{\text{3}^{2}}={\text{3}^{12+2}}={\text{3}^{14}}$ □.

$\therefore$ the answet is $\color{#3D99F6}{\text{3}^{14}}$ .