For the above inequality to be true, , where and are positive integers, find the minimum value of + + .
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Clearly, the left -hand side of the above inequality can be transformed into a quadratic with a simple substitution, y = 3 x Therfore,
4 y 2 − 1 9 y + 1 2 ≤ 0 => ( y − 4 ) ( 4 y − 3 ) ≤ 0
Now, plotting the w a v y − c u r v e for the above inequality we find that this inequality exists only when y ∈ [ 3 / 4 , 4 ]
Replacing y = 3 x again, we get:
3 x ≤ 4 a n d 3 x ≥ 3 / 4
Therefore,
x ≤ l o g 3 4 a n d x ≥ l o g 3 3 / 4
HENCE,
x ∈ [ l o g 3 3 / 4 , l o g 3 4 ] :)