3 ∣ x − y ∣ + 3 ∣ y − z ∣ + 3 ∣ z − x ∣ − 6 x 2 + 6 y 2 + 6 z 2
Let x , y and z be real numbers satisfying x + y + z = 0 , find the minimum value of the expression above.
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What about maximizing x^2+y^2+z^2 for min p?
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Yeah that also could work... The thing is that i thought would be easier this way so if you know how to do that, could you please post that solution.
Its quite obvious that x , y and z = 0. If any one of them would have been non zero, then |x-y| , |y-z| and/or |z-x| ( and also x² , y² and z²) would be greater than 0 which would lead this sum to a much greater value than 3. Its common logic
The given equation is cyclic. Clearly then x= y = z. Here that implies that x = y = z = 0.
This leads us to our answer.
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