Exponentiation, Subtraction and Multiplication

Algebra Level 1

( 2 4 4 2 ) ( 5 7 7 5 ) = ? \large (2^4-4^2)(5^7-7^5)= \, ?


The answer is 0.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

4 solutions

Hung Woei Neoh
Dec 20, 2016

( 2 4 4 2 ) ( 5 7 7 5 ) = ( 16 16 ) ( 5 7 7 5 ) = 0 ( 5 7 7 5 ) = 0 (2^4-4^2)(5^7-7^5) = (16-16)(5^7-7^5) = 0(5^7-7^5) = \boxed{0}

2 4 4 2 2^4 - 4^2 = = 16 16 16 - 16 = 0 =0 , any number multiplied by 0 0 is 0 0 , therefore the answer is 0 0 .

Prokash Shakkhar
Dec 16, 2016

Here, 2 4 4 2 = 0 2^4 -4^2 =0 ..So, Finding out the value of 1st part factor 2 4 4 2 2^4 -4^2 is to find out the product.. Answer is \boxed{\color\red{0}}

Mahdi Raza
Jun 3, 2020

2 4 4 2 = 0 2^4 - 4^2 = 0

( 0 ) ( 5 7 7 5 ) = 0 \implies (0)(5^7-7^5) = \boxed{0}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...