Exponents

Algebra Level 3

Solve for b in the following system of equations:

8 a + b 8^{a+b} = 4 2 4\sqrt{2}

8 b + c 8^{b+c} = 2 4 \frac{\sqrt{2}}{4}

8 a + c 8^{a+c} = 8


The answer is -0.33.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Sharad Roy
May 1, 2014

8 a + b = 4 2 2 3 a + 3 b = 2 5 / 2 3 a + 3 b = 5 2 6 a + 6 b = 5 a + b = 5 6 . . . . . . . . . . . . e q ( 1 ) S i m i l a r l y , 8 b + c = 2 16 2 3 b + 3 c = 2 3 / 2 6 b + 6 c = 3 . . . . . . . . . . . . e q ( 2 ) S i m i l a r l y , 8 a + c = 8 a + c = 1 c = 1 a . . . . . . . . . . . . . . . . e q ( 3 ) F r o m e q ( 2 ) & e q ( 3 ) , w e g e t : a b = 3 2 . . . . . . . . . . . . . . . . . . e q ( 4 ) B y S u b t r a c t i n g e q ( 1 ) f r o m e q ( 4 ) , w e g e t : 2 b = 4 6 b = 4 6 × 2 b = 1 3 b = 0.33 { 8 }^{ a+b }\quad =\quad 4\sqrt { 2 } \quad \quad \quad \\ \Rightarrow \quad { 2 }^{ 3a+3b }\quad =\quad { 2 }^{ 5/2 }\\ \Rightarrow \quad 3a+3b\quad =\quad \frac { 5 }{ 2 } \\ \Rightarrow \quad 6a+6b\quad =\quad 5\\ \Rightarrow \quad a+b\quad =\quad \frac { 5 }{ 6 } \quad ............{ eq }(1)\\ \\ \\ Similarly,\\ \\ { 8 }^{ b+c }\quad =\quad \sqrt { \frac { 2 }{ 16 } } \\ \Rightarrow \quad { 2 }^{ 3b+3c }\quad =\quad { 2 }^{ -3/2 }\\ \Rightarrow \quad 6b+6c\quad =\quad -3\quad ............eq(2)\\ \\ \\ Similarly,\\ \\ { 8 }^{ a+c }\quad =\quad 8\\ \Rightarrow \quad a+c\quad =\quad 1\\ \Rightarrow \quad c\quad =\quad 1-a\quad ................eq(3)\\ \\ \\ From\quad eq(2)\quad \& \quad eq(3),\quad we\quad get:\\ \\ a-b\quad =\quad \frac { 3 }{ 2 } ..................eq(4)\\ \\ By\quad Subtracting\quad eq(1)\quad from\quad eq(4),\quad we\quad get:\\ \\ -2b\quad =\quad \frac { 4 }{ 6 } \\ \Rightarrow \quad b\quad =\quad -\frac { 4 }{ 6\times 2 } \\ \Rightarrow \quad b\quad =\quad -\frac { 1 }{ 3 } \\ \therefore \quad b\quad =\quad -0.33\\ \\ \\

perfect

Krishna Ramesh - 7 years, 1 month ago

Accuracy of decimal points isn't given . - 1/3 is a never-ending decimal.

I got -0.3 and it's wrong.

William Isoroku - 6 years, 10 months ago
Kenneth Tay
Jul 13, 2014

(1) × \times (2) / (3): 8 2 b = 1 4 , 8 b = 1 2 , b = 1 3 . 8^{2b} = \frac{1}{4}, \\ 8^b = \frac{1}{2}, \\ b = -\frac{1}{3}.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...