Expressions

We know that, Greatest number divisible by 8 formed using 2,4,6 only once is 624.(8x78). Such that smallest no. is 264(8x33). Difference=624-264 => 360 (ans.)

well. for a number to be divisible by 8........ the last TWO digits of the number should be divisible by 8 ! and the number is a 3 digit no. given the conditions! so the last TWO digits can be either 24 or 64. so smallest no. is 264 & greatest no. is 624. difference= 624-264=360

Using the digits 2,4,6 once, the biggest number we get is 642. But 642 is not divisible by 8, so we go on to 624 which is divisible by 8. In the same way, we get the smallest is 264 Thus, the difference between them is 360

624 is the greatest number by using 2,6 and 4 digit only onces and divided by 8 264 is the smallest number by using 2,6 and 4 digit only onces and divided by 8 therefore the difference between greater number and smallest number is 624-264=360

We all know that there can be 6 possible numbers, so just use the divisibility 8 rule to know the smallest and the biggest, then subtract smallest to biggest.

the greatest no will be 624 and the smallest no will be 264 the difference of these no are 360

greatest number that is formed from 2,4 and 6 digit each only once and divisible by 8 =624

smallest number that is formed from 2,4 and 6 digit each only once and divisible by 8 =264

thus difference between the greatest and smallest number which are divisible by 8

=>624-264=360 that is answer.

for it to be divisible by 8 the last 3 digits should be divisible by 8 here greatest no. formed = 624 smallest no. formed = 264 the difference = 624-264 = 360

The Greatest no. formed by 2,4,6 divisible by 8 is 624 .

The Smallest no. formed by 2,4,6 divisible by 8 is 264 so Their Difference will be 360 .

check for numbers...we first find 264 which is smallest that i divisible by 8 and then 624 which is greatest.....calculate the difference 624-264=360

For the largest number, we look for a number beginning with $6$ . As a quick check $600\equiv 0\pmod{8}$ therefore we need the last two digits to be divisible by 8. Among 24 and 42, only 24 is divisible by 8 therefore the largest such number is 624. The smallest will likely begin with 2. We notice that $200\equiv 0\pmod{8}$ therefore we need the last two digits to be divisible by 8. Notice that 64 is and 46 isn't, therefore the smallest is $264$ . The answer is henceforth $624-264=\boxed{360}$

An easy way to solve this is by using simple brute force, since there are only 6 numbers that can be formed using this three digits. The highest number formed by these numbers is $642$ , which is not divisible by $8$ . The next is $624$ , which visibly is. Similarly, the smallest such number should be $264$ . Hence, the answer is $624 - 264 = 360$ .