Extension in Spring due to Magnetic force!

The circuit in figure consists of wires at the top and bottom and identical metal springs as the left and right sides. The wire at the bottom has a mass of 10 g 10 \text{ g} and is 5 cm 5 \text{ cm} long. The wire is hanging as shown in the figure. The spring stretch 0.5 cm 0.5 \text{ cm} under the weight of the wire and the circuit has a total resistance of 12 Ω 12 \Omega . When the lower wire is subjected to a static magnetic field, the springs stretch an additional 0.3 cm 0.3 \text{ cm} . The magnetic field is?

1.2 T and directed out of page None of These 0.6 T and directed into the plane of page 1.2 T and directed into the plane of page 0.6 T and directed out of page

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1 solution

Nishant Rai
May 27, 2015

Draw The FBD of the system.

When magnetic field is on, in equilibrium, K Δ L = m g + B i L K\Delta L = mg + BiL

B = K Δ L m g i L = ( m g Δ l Δ l 0 m g ) V R L \large \Rightarrow B = \frac{K\Delta L - mg}{iL} = \frac{(\frac{mg\Delta l }{\Delta l_0}-mg)}{\frac{V}{R}L} (where Δ l 0 \Delta l_0 is the expansion when no magnetic field is on.)

Magnetic field must be of out of the page as magnetic force is downward.

Should`nt the magnetic field out of the plane. As current moves from higher to lower potential and current will be in right direction so using Fleming's rule force is downward . Magnetic field out of paper

Kyle Finch - 6 years ago

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Plz reply @Nishant Rai

Kyle Finch - 6 years ago

you're correct, while writing the solution, i missed "out of the page". Sorry for the trouble.

@Kyle Finch

Nishant Rai - 6 years ago

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