Extraordinary Differential Equations #11

Calculus Level 3

Newton's Law of Cooling states that the rate at which a hot object cools down is directly proportional to the temperature difference between itself and its environment.

Suppose an object at 100. 0 C 100.0^{\circ} \text{C} is left to cool down in an environment of a fixed lower ambient temperature. If the object's temperature is 80. 0 C 80.0^{\circ} \text{C} after an hour, and 54. 6 C 54.6^{\circ} \text{C} after another 2 hours, calculate the ambient temperature of the surrounding temperature in C ^{\circ} \text{C} .

(This problem is part of the set Extraordinary Differential Equations .)

40 15 35 25 20 30

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...