Consider the differential equation on a series of cosine functions involving : where . Determine the value of .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Notice that if there is an equilibrium solution to the ODE, y ( x ) = 2 π for all x , whereby y ′ ( x ) = d x d 2 π = 0 for all x , y ′ ( x ) = ∑ k = 1 2 0 1 7 k cos ( ( 2 k − 1 ) ( 2 π ) ) = 0 for all x , and this also satisfies the initial condition y ( 0 ) = 2 π . Thus, π y ( 2 0 1 7 ) = 2 π × π 1 = 2 1 .