Let be a polynomial with degree and let denotes the derivative of , if it exists such that find the reciprocal of the leading coefficient of .
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Let P ( x ) = a 5 x 5 + a 4 x 4 + ⋯ + a 0 , then P ′ ( x ) = 5 a 5 x 4 + 4 a 4 x 3 + ⋯ + a 1 , calculate the composite function: P ′ ( P ( x ) ) = 5 a 5 ( a 5 x 5 + ⋯ ) 4 + ⋯ P ( P ′ ( x ) ) = a 5 ( 5 a 5 x 4 + ⋯ ) 5 + ⋯
Since the leading term of these two is only 5 a 5 5 x 2 0 and 5 5 a 5 6 x 2 0 , they must be equal, so we ended up a 5 = 6 2 5 1 , the desired reciprocal is 6 2 5 .
This problem is inspired by the book Putnam and Beyond Question No.166.
Using similar process, any polynomial with degree n ≥ 2 must have leading coefficient a n = n n − 1 1 .