An algebra problem by Mahmoud Khattab

It can be written as $\frac{2^{12}}{2^7}=2^{12-7}=2^5=\boxed{32}$

$\frac{4096}{128}$

= $\frac{2^{12}}{2^7}$

= ${2^5}$

=32

Just from looking at the problem, you can see that both the numerator and denominator are powers of $2$ (since $\frac{2^x}{2^y} = 2^{x-y}$ by the laws of exponents), so you know that the answer is a power of $2$ . The only option that is a power of $2$ is $32$ , so $32$ must be the answer.

Same here, Abdur Rehman Zahid! It is interesting to use the law of indices.

come on man just use the calculator