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This problem is pretty interesting as it takes value in denominator as one of the factors... (I find it pretty subjective, if we should do so or not, but well)
From the problem we have one factor: 3 .
If we would divide numerator by 3 , we would get:
3 6 2 − 1 1 2
Which is the same as:
( 3 6 − 1 1 ) ( 3 6 + 1 1 ) = 2 5 × 4 7
The factors of 2 5 are 5 and 5 . 4 7 is a prime number, so it has no factors other than itself.
And so, we have our problem solved!
Answer: the factors are: 5 , 5 , 4 7 , 3 .