Factorial angles

Geometry Level 2

Determine the least positive integer value of n n for which sin ⁡ ( n ! ) = 0 \sin(n!)=0 . The angle is in degrees.

7 6 12 10

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2 solutions

Matin Naseri
Feb 2, 2018

sin ⁡ ( n ! ) = 0 \sin{(n!)=0} .

Because of we need the least value we select the minimum number.

(6<7<10<12) \text{(6<7<10<12)}

6!=720 \text{6!=720}

sin ⁡ ( 720 ) = 0 \sin{(720)}={0}

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6!=720 Hence sine of 720 degrees=0, because it is an integer multiple of 180 degrees.

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Please change the topic of problem into (Geometry) \text{(Geometry)} .

I think this is not A Number Theory \text{Number Theory} problem.

Matin Naseri - 3 years, 4 months ago

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