Factorial dare

Number Theory Level 1

x ! = ( x + 1 ) ! x!=(x+1)!

What is the value of x x satisfying this equation?


The answer is 0.

Prashant Goyal by prashant goyal , 23, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Kay Xspre
Oct 5, 2015

Dividing both sides with x ! x! gives 1 = x + 1 1 = x+1 or x = 0 x = 0 . You can have x = 0 x=0 as 0 ! = 1 0! = 1

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...