factorial in roots

Just square $x,y,z$ and get, $x^{2}=10!*10,y^{2}=10!*81,z^{2}=10!*11\\ \Rightarrow\ y>z>x.$

Square each of p,q and r, then carry out division as follows: $r^{2}$ / $q^{2}$ = 11!/10! * 81 = 11/81 <1. Therefore, $r^{2}$ < $q^{2}$ or simply r < q (1). Now repeat with q and p: $q^{2}$ / $p^{2}$ = 81 * 10!/100 * 9! = 81 * 10/100 = 81/10 >1 (2). It follows that q > p. Similarly: $r^{2}$ / $p^{2}$ = 11!/100 * 9! = 11 * 10/100 = 11/10 >1, so r > p (3). From equations (1), (2) and (3): q > r > p

Take out 10 from root in q and its around 3 so its 27 times and p is 10 times take out 110 from r you get around 10 times of 9 fact in root hence its clear that and is q