Factorial Power

20 1 7 ! × 7 201 ! \large 201^{7!} \times 7^{201!}

Find the number of trailing zeroes of the above number?

Notation: ! ! is the factorial function. For example, 8 ! = 1 × 2 × 3 × × 8 8! = 1\times2\times3\times\cdots\times8


The answer is 0.

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1 solution

Ravneet Singh
Jul 14, 2017

To make a zero we need a 2 and a 5. For that let's consider the last digit of each number.

( 201 ) 7 ! = ( 201 ) 5040 \large (201)^{7!} = (201)^{5040} , will end in 1, since the unit digit is 1.

7 201 ! \large 7^{201!} will also not end either in 2 or 5 because 7 raised to any power will end only in 7,9,3 or 1. Since we will not get any 2 or 5 at the end to make a zero, therefore number of trailing zeroes = 0 = \boxed{0} .

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