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I completely agree that the undefined answer should be removed. Factorial is not the same as gamma; that's like saying that the floor function is the same as f ( x ) = x . Just because they spit out the same values when x is natural doesn't mean they're the same. It felt a little bit like a trick to me.
By definition, we have n ! = Γ ( n + 1 ) , the Gamma Function. Now ( − 2 1 ) ! = Γ ( 2 1 ) = π by Euler's Reflection Formula, Γ ( z ) Γ ( 1 − z ) = sin ( π z ) π .
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n ! = Γ ( n + 1 ) ( − 1 / 2 ) ! = Γ ( 1 / 2 ) Γ ( 1 / 2 ) = ∫ 0 ∞ x − 1 / 2 e − x d x Let x = u 2 . Then Γ ( 1 / 2 ) = ∫ 0 ∞ 2 e − u 2 d u = ∫ − ∞ ∞ e − u 2 d u This is a famous integral that eluded early attempts to solve, since there is no elementary antiderivative. The definite integral above, though, can be evaluated as π .
By the way, even today, factorial is typically defined only for nonnegative integers, so I think the "undefined" answer should be replaced with a different answer so that people do not think you are referring to the classical definition ∏ k = 1 n k which is undefined for n = − 1 / 2 .