factoring factorials

How many factors does 10 ! 10! have ?


The answer is 270.

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1 solution

The prime factorization of 10 ! 10! is 2 8 3 4 5 2 7 2^{8} * 3^{4} * 5^{2} * 7 .

Thus the number of (positive) factors is

( 8 + 1 ) ( 4 + 1 ) ( 2 + 1 ) ( 1 + 1 ) = 270 (8 + 1)(4 + 1)(2 + 1)(1 + 1) = \boxed{270} .

An explanation of this calculation is given here .

nice solution

math man - 6 years, 9 months ago

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