Factoring Practice
Level
2
What is the largest integer in the prime factorization of ?
The answer is 401.
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1 solution
1 5 9 9 9 9 = 1 6 0 0 0 0 − 1 = 2 0 4 − 1 = ( 2 0 + 1 ) ( 2 0 − 1 ) ( 2 0 2 + 1 ) = 3 ∗ 7 ∗ 1 9 ∗ 4 0 1