Factorizing An Absolute Value Expression?

Algebra Level 3

Let the largest root of x 2 + 5 x 6 = 0 x^2+|5x|-6=0 be a a and the smaller root of x 2 + 5 x 6 = 0 |x^2+5x|-6=0 be b b .

Find a + b a+b .

Notation : | \cdot | denotes the absolute value function .


The answer is -5.

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1 solution

Rishabh Jain
Jul 16, 2016

Relevant wiki: Absolute Value Equations - Intermediate

First equation:- x 2 + 5 x 6 = 0 ( x + 6 ) ( x 1 ) = 0 x = 6 , 1 |x|^2+5|x|-6=0\implies (|x|+6)(|x|-1)=0\implies |x|=-6,1

Since x 0 |x|\ge 0 , we get x = 1 x = ± 1 |x|=1\implies x=\pm 1 .

Hence x = ± 1 x=\pm 1 .

Second equation:-

{ x 2 + 5 x 6 = 0 if x ( , 5 ) ( 0 , ) x 2 + 5 x + 6 = 0 if x [ 5 , 0 ] \begin{cases} x^2+5x-6=0 &\textrm{if } x\in (-\infty,-5)\cup (0,\infty)\\x^2+5x+6=0 & \textrm{if }x\in [-5,0]\end{cases}

Taking care of intervals we get x = 6 , 1 x=-6,1 in first case while in second case we get x = 3 , 2 x=-3,-2

Hence x = 6 , 3 , 2 , 1 x=-6,-3,-2,1 .


The larger root in first equation is 1 1 while smaller in the second equation is 6 -6 . Hence 6 + 1 = 5 -6+1=\large\boxed{-5} .

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