Let the largest root of be and the smaller root of be .
Find .
Notation : denotes the absolute value function .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Relevant wiki: Absolute Value Equations - Intermediate
First equation:- ∣ x ∣ 2 + 5 ∣ x ∣ − 6 = 0 ⟹ ( ∣ x ∣ + 6 ) ( ∣ x ∣ − 1 ) = 0 ⟹ ∣ x ∣ = − 6 , 1
Since ∣ x ∣ ≥ 0 , we get ∣ x ∣ = 1 ⟹ x = ± 1 .
Hence x = ± 1 .
Second equation:-
{ x 2 + 5 x − 6 = 0 x 2 + 5 x + 6 = 0 if x ∈ ( − ∞ , − 5 ) ∪ ( 0 , ∞ ) if x ∈ [ − 5 , 0 ]
Taking care of intervals we get x = − 6 , 1 in first case while in second case we get x = − 3 , − 2
Hence x = − 6 , − 3 , − 2 , 1 .
The larger root in first equation is 1 while smaller in the second equation is − 6 . Hence − 6 + 1 = − 5 .