Facts-6

Geometry Level 3

In a △ A B C \triangle ABC , ∠ A = 3 0 ∘ \angle A=30^\circ , B C = 6 BC=6 . What is the circumradius of this triangle?


The answer is 6.

Ayush G Rai by Ayush G Rai , 20, India

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1 solution

Ayush G Rai
Jun 23, 2016

If R R is the circum-radius of the circum-circle then 2 R = B C s i n A 2R=\dfrac{BC}{sinA} (extended sin rule)
Therefore R = B C 2 s i n A = 6 2 s i n 3 0 ∘ = 6 c m . R=\dfrac{BC}{2sinA}=\dfrac{6}{2sin30^\circ}=\boxed{6cm}.
Note: If in a triangle,one angle is 3 0 ∘ 30^\circ opposite side is equal to its circum-radius in length.

2 Helpful 0 Interesting 0 Brilliant 0 Confused

Actually it is called extended sine rule not only sine rule .

Chirayu Bhardwaj - 4 years, 11 months ago

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yup.thanks for reminding me

Ayush G Rai - 4 years, 11 months ago

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