Fair Die Game
In a game , the player throws a fair die repeatedly until he obtains a number that has already appeared in that turn , which means he must have at least 2 throws but not more than 7 throws.
Find the probability that the player has fewer than 4 throws in a turn.
Give your answer to 3 decimal places.
You may use a calculator.
The answer is 0.444.
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1 solution
(6/6 x 1/6) + 2 (6/6 x 5/6 x 1/6)
= 4/9
= 0.444 (3 decimal places)