At what height(in km) the acceleration due to gravity decreases by 36% of its value on the surface of earth?
(Consider radius of earth to be 6400 km)
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(( R)^2)/((R + h)^2) = 0.64 .............. which implies (R/(R + h)) = 0.8 ........... put R =6400 and simplify ......... you will get h = 1600 ( don't use the formula ( (g')/(g)= (1 - (2h/R) ) ..as it is used when h<<R ) !