Let be a triangle with area equal to , and are interior points of the sides , respectively.
Let be the intersecting point of and .
Find the maximum value of the area of triangle .
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If AB BD = a and AC CE = b , it’s fairly straightforward using Menelaus’ theorem to show DEF ’s area to be a + b − a ⋅ b a ⋅ b ⋅ ( 1 − a − b + a ⋅ b ) of ABC ’s. Maximizing this numerically yields a = b ≈ 0 . 3 8 1 9 7 , making the answer ≈ 9 . 0 1 7 .