Family Functions Related to Phi

Algebra Level 3

Let f n ( x ) f_n(x) be a family of quadratics with integer coefficients in the form a x 2 + b x + c ax^2+bx+c such that at least one of its roots is ϕ \phi , which is 1 + 5 2 \frac{1+\sqrt{5}}{2} . There exists a quadratic in the family f n ( x ) f_n(x) such that the sum a + b + c = 1 a+b+c=-1 . The name of this particular function is f ( x ) f_{\star}(x) . Find f ( 16 ) f_{\star}(16) .


The answer is 239.

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1 solution

Daniel Liu
Apr 12, 2014

Note that the second root must be the conjugate of the first root, or 1 5 2 \dfrac{1-\sqrt{5}}{2} . Thus, the quadratic is ( x 1 + 5 2 ) ( x 1 5 2 ) = x 2 x 1 \left(x-\dfrac{1+\sqrt{5}}{2}\right)\left(x-\dfrac{1-\sqrt{5}}{2}\right)=x^2-x-1 . Since this quadratic fits the condition that a + b + c = 1 a+b+c=-1 , then it is our desired quadratic, and so our answer is 256 16 1 = 239 256-16-1=\boxed{239} .


*Note: * Even if a + b + c = n a+b+c=n for any n n , we can still solve for the quadratic by multiplying the entire thing by a constant such that a + b + c = n a+b+c=n .

This is how I solved it perfectly. Why did you have to beat me to the solution?

Sharky Kesa - 7 years, 2 months ago

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Yes! Dude, he always beats me to the solution! Arg! :D

Finn Hulse - 7 years, 2 months ago

What cool about the family is that any quadratic in the form a x 2 a x a ax^2-ax-a will have a root of ϕ \phi ! So usually its just luck if you stumble upon the function the very first time. Check out some other uses for this equation here !

Finn Hulse - 7 years, 2 months ago

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