Family of 3's

Level 2

3 3 2 3 3 a 4 a 3 a 2 a 1 = ? \large \sqrt[a_1]{3 \ \sqrt[a_2]{3^2 \ \sqrt[a_3]{3^3 \ \sqrt[a_4]{\cdots}}}}= \ ?

where a n = 3 n + 1 a_n=3n+1 . Report your answer to two decimal places.


The answer is 1.44.

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2 solutions

Chew-Seong Cheong
Oct 24, 2017

x = 3 3 2 3 3 13 10 7 4 = ( 3 ( 3 2 ( 3 3 ( ) 1 13 ) 1 10 ) 1 7 ) 1 4 = 3 1 4 3 2 1 4 1 7 3 3 1 4 1 7 1 10 = exp ( ln 3 ( 1 4 + 2 1 4 1 7 + 3 1 4 1 7 1 10 + ) ) where exp ( x ) = e x . = exp ( 1 3 ln 3 ) See note. = 3 3 1.44 \begin{aligned} x & = \sqrt[4]{3 \sqrt[7]{3^2\sqrt[10]{3^3\sqrt[13]{\cdots}}}} \\ & = \left(3 \left(3^2 \left(3^3 \left(\cdots \right)^\frac 1{13} \right)^\frac 1{10} \right)^\frac 17 \right)^\frac 14 \\ & = 3^\frac 14 \cdot 3^{2 \cdot \frac 14 \cdot \frac 17} \cdot 3^{3 \cdot \frac 14 \cdot \frac 17 \cdot \frac 1{10}} \cdots \\ & = \exp \left(\ln 3 {\color{#3D99F6} \left(\frac 14 + 2 \cdot \frac 14 \cdot \frac 17 + 3 \cdot \frac 14 \cdot \frac 17 \cdot \frac 1{10} + \cdots \right)} \right) & \small \color{#3D99F6} \text{where }\exp (x) = e^x. \\ & = \exp \left({\color{#3D99F6}\frac 13} \ln 3\right) & \small \color{#3D99F6} \text{See note.} \\ & = \sqrt[3] 3 \approx \boxed{1.44} \end{aligned}


Note: See the proof of n = 1 n k = 1 n ( 3 k + 1 ) = 1 3 \displaystyle \sum_{n=1}^\infty \frac n{\prod_{k=1}^n (3k+1)} = \frac 13

Please have a look at A Nested Radical it has got a full discussion on this and on the infinite series you have mentioned at the bottom

Mrigank Shekhar Pathak - 3 years, 7 months ago

View A Nested Radical . It has got a full discussion on how this nested radical and some of its friends are formed as well as how an infinite series from this is concluded.

@Mrigank Shekhar Pathak , sir, I need your help on some mathematics topics.

Mr. India - 2 years, 3 months ago

I will be glad to help you

Mrigank Shekhar Pathak - 2 years, 3 months ago

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@Mrigank Shekhar Pathak , can you tell me some books on calculus, number theory and other topics (I am still in 10th and have just basic knowledge of these topics)

Mr. India - 2 years, 3 months ago

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for calculus you can use 'Calculus of One Variable - IA Maron' for problem solving and 'Calculus - Tom M Apostol' for theory building; for Number Theory you can use 'Number Theory - David M Burton' and then move to 'Number Theory - Ivan Niven'; for Combinatorics you can use 'Combinatorics - Chen Chuan Chong';for Trigonometry you can use 'Trigonometry part 1 and 2 - S.L Loney'; for Geometry you can use 'Coordinate Geometry - S.L Loney'; for general Olympiad preparation you can use 'Pre-College Mathematics' and Olympiad book by Arrihant publisher. Thank You

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