a 1 3 a 2 3 2 a 3 3 3 a 4 ⋯ = ?
where a n = 3 n + 1 . Report your answer to two decimal places.
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Please have a look at A Nested Radical it has got a full discussion on this and on the infinite series you have mentioned at the bottom
View A Nested Radical . It has got a full discussion on how this nested radical and some of its friends are formed as well as how an infinite series from this is concluded.
@Mrigank Shekhar Pathak , sir, I need your help on some mathematics topics.
I will be glad to help you
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@Mrigank Shekhar Pathak , can you tell me some books on calculus, number theory and other topics (I am still in 10th and have just basic knowledge of these topics)
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for calculus you can use 'Calculus of One Variable - IA Maron' for problem solving and 'Calculus - Tom M Apostol' for theory building; for Number Theory you can use 'Number Theory - David M Burton' and then move to 'Number Theory - Ivan Niven'; for Combinatorics you can use 'Combinatorics - Chen Chuan Chong';for Trigonometry you can use 'Trigonometry part 1 and 2 - S.L Loney'; for Geometry you can use 'Coordinate Geometry - S.L Loney'; for general Olympiad preparation you can use 'Pre-College Mathematics' and Olympiad book by Arrihant publisher. Thank You
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x = 4 3 7 3 2 1 0 3 3 1 3 ⋯ = ( 3 ( 3 2 ( 3 3 ( ⋯ ) 1 3 1 ) 1 0 1 ) 7 1 ) 4 1 = 3 4 1 ⋅ 3 2 ⋅ 4 1 ⋅ 7 1 ⋅ 3 3 ⋅ 4 1 ⋅ 7 1 ⋅ 1 0 1 ⋯ = exp ( ln 3 ( 4 1 + 2 ⋅ 4 1 ⋅ 7 1 + 3 ⋅ 4 1 ⋅ 7 1 ⋅ 1 0 1 + ⋯ ) ) = exp ( 3 1 ln 3 ) = 3 3 ≈ 1 . 4 4 where exp ( x ) = e x . See note.
Note: See the proof of n = 1 ∑ ∞ ∏ k = 1 n ( 3 k + 1 ) n = 3 1