Far, far away?

If you have not done the previous set , I recommend you do it first.

Once we have the concept of synchronized clocks and a definition of how to relate the time coordinates of observers at different points we can define a distance. Let's choose a region of space with a family of observers moving through it, all with clocks synchronized by sending light pulses back and forth. Before when dealing with time we used the variable F F for Finn's time and A A for Aaron's time. Since we now have synchronized clocks, we can define a variable t t as the coordinate time which is a valid, well defined coordinate everywhere in the region of interest.

Consider the scenario where Finn and Aaron are communicating with light pulses. At time t t 1 _1 , Finn sends a light pulse to Arron, who reflects is back, and is received by Finn at time t t 2 _2 . Which of these is a possible definition for the distance x x between Finn and Aaron?

x = t 2 x=t_2 x = ( t 2 + t 1 ) / 2 x=(t_2+t_1)/2 x = t 1 x=t_1 x = ( t 2 t 1 ) / 2 x=(t_2-t_1)/2

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1 solution

Siam Habib
Jun 25, 2014

First of all notice that x = t 1 x = t_1 is not true. Because on that case, if Finn sent a light pulse 5 5 minutes later, the distance would increase.

Similarly, x = t 2 x = t_2 can't also be true. Because on that case , if Finn had sent a light pulse 5 5 minutes earlier, the light pulse would return 5 5 minutes earlier and the distance would decrease.

Same goes for, x = t 1 + t 2 2 x = \frac{t_1+t_2}{2} .[ If Finn had sent it x x minutes earlier or later the distance would decreased or increased x x ]

Now, let's examine the option x = t 1 t 2 2 x = \frac{t_1-t_2}{2} . On this case distance is independent to when the event occurs. So, this is our answer.

Also, notice that d i s t a n c e = v e l o c i t y Δ t i m e distance = velocity\Delta time . On this case v e l o c i t y velocity is just considered as 1 1 . So, this indeed our answer.

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