Kana-chan has an urgent meeting at a faraway place, and has to travel by car from City A to City C in the shortest time possible. She travels from A to B at a (constant) speed of 60 kph, and from B to C at 80 kph, reaching her destination in 8.5 hours. After the meeting, she returns from C to B at 60 kph, and from B to A at 80 kph, taking her 9 hours on the return trip.
In kilometers, how far is City A from City C?
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Let A B be the distance from A to B (or from B to A), and B C be the distance from B and C (or from C to B). Since t i m e = s p e e d d i s t a n c e , the trip from A → B → C is given by
6 0 A B + 8 0 B C = 8 . 5
while the trip from C → B → A is given by
6 0 B C + 8 0 A B = 9
Solving the equations simultaneously, we obtain A B = 2 4 0 and B C = 3 6 0 , giving A C = A B + B C = 6 0 0 k m .