Induced electromotive force

Four sections A A through D D in the above graph show the changes in the magnetic field intensity in a circular coil as time passes. Find the ordered pair of sections where the respective magnitudes of electromotive forces are the (largest, smallest) . \text{(largest, smallest)}.

(B, D) (D, A) (A, C) (A, D)

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5 solutions

Ajinkya Kulkarni
Apr 13, 2014

Faraday's 2 nd law of electromagnetic induction ...the amount of emf induced in the coil is directly proportional to rate of change of flux linking with coil...

Arijit Banerjee
Mar 13, 2014

at c dB/dT =0 so emf induced is also 0 ... and in A the slope is high that is dB/dT is high hence emf induced is high.. flux = B * A (B= Field intensity and A is the area ) d(flux)/dT = A * dB/dT Emf = A * dB/dT

Adnan Afzal
Mar 10, 2014

it,s clear from graph.

Piu Das
Jul 26, 2014

In c the magnetic field is constant with time as evident from the graph , consequently there wont be any change in flux hence by Faraday's without change in flux emf induced =0

According to Faraday's law: d E = d T d t dE = \frac{dT}{dt} -- which is actually the slope of the given graph.
Therefore, for region A slope is maximum and hence dE is Maximum and for region C the slope is zero and dE is Minimum
Hence, A and C is the right answer.

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