Farhan's problem on square roots
Algebra
Level
pending
If a=(1+√1001)/2 then find the value of (4a³-1004a-1001)^1001
The answer is -1.
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1 solution
a=(1+√1001)/2 2a-1=√1001 4a²-4a-1000=0 Now, (4a³-1004a-1001)^1001={(4a³-4a²-1000a)+(4a²-4a-1000)-1}^1001=(0-0-1)^1001=-1