Farm

Algebra Level 1

Old McDonald has a farm. There are currently 3 sheep and 5 cows in the barn. After bringing in an additional 10 animals, there are an equal number of cows and sheep in the barn. How many sheep and cows did Old McDonald bring in?

6 sheep, 4 cows 4 sheep, 6 cows 5 sheep, 5 cows

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

x x = number of sheeps added

y y = number of cows added

x + y = 10 \boxed{x+y=10} ( 1 ) \color{#D61F06}(1)

3 + x = 5 + y 3+x=5+y \color{#3D99F6}\large \implies x y = 2 \boxed{x-y=2} ( 2 ) \color{#D61F06}(2)

Adding ( 1 ) \color{#D61F06}(1) and ( 2 ) \color{#D61F06}(2) , we get

x = 6 \large \color{plum}\boxed{x=6}

It follows that

y = 4 \large \color{plum}\boxed{y=4}

Aman Dubey
Jul 20, 2017

Total number of animals (after bringing 10 animals ) will be 18. So there are 9 sheeps and 9 cows. So we need 6 more sheeps (we have 3 with us) and 4 more cows (we have 5 with us).

Samuel Moreno
Jul 19, 2017

x = x = number of sheep added. x + 3 = 5 + ( 10 x ) x+3 = 5+(10-x)

x + 3 = 15 x x+3 = 15-x

2 x = 12 2x = 12

x = 6 x = 6

Therefore 6 sheep and 10-6 = 4 cows

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...