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The acceleration of athletes in certain sports is very important. For example, in American football times are recorded during sprints after an athlete has run 9 m to measure the acceleration of the athlete. A very fast wide receiver (someone who runs down the field to catch passes thrown to them) will cover those 9 meters in 1.4 seconds. What is the acceleration of the wide receiver in m/s 2 \mbox{m/s}^2\, assuming the receiver starts from rest and the acceleration is constant?


The answer is 9.18.

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1 solution

David Mattingly Staff
May 13, 2014

Since the acceleration is a constant and the receiver starts from rest, the distance traveled is given by d = 1 2 a t 2 d=\frac {1} {2} a t^2 . Solving for a a yields a = 9.18 m/s 2 a=9.18~\mbox{m/s}^2 .

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