Father And Son

Algebra Level 1

The sum of the ages of a father and his son is 52. 3 years ago, father's age is two years more than thrice the sons age. Find the age of the son 2 years from now.


The answer is 16.

Siddhant Mahurkar by Siddhant Mahurkar , 25, India

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5 solutions

Uahbid Dey
Mar 31, 2014

f + s = 52 = > f = 52 − s f+s=52\;=>f=52-s a n d f − 3 = 2 + 3 ( s − 3 ) and\;f-3=2+3(s-3) = > 52 − s − 3 = 2 + 3 s − 9 =>52-s-3=2+3s-9 = > 4 s = 52 − 3 − 2 + 9 =>4s=52-3-2+9 = > s + 2 = 16 =>s+2=16

2 Helpful 0 Interesting 0 Brilliant 0 Confused

X + Y = 52; (X -3) = 3 (Y -3) + 2; Y = 14

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Jia Quan Ng
Apr 2, 2014

Father +Son Age=52

3 years ago = 52- (3x2)-Two people

=46

(46-2)/(3+1)=44/4=11

Son is 11 years old 3 years ago

So 3years+2years=5years.

11=5=16

Son is 16 years old after 2 years

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Shamima Shimu
Apr 1, 2014

Let the age of son = x & Father's age = 52 - x

Then, 3 years ago the eqn like below:

52 - x - 3 = 3(x-3) + 2

x = 14

So, after 2 yrs son's age will be 16.

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Venture Hi
Mar 26, 2014

f=father's age, s=son's age Find the equality

f+s=52, f-3=3(s-3)+2 f=38, s=14 Two years from now son will be 16.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

right answer

PRADEEP Chauhan - 7 years, 2 months ago

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