A pendulum clock is mounted in an elevator car which starts going up at a uniform acceleration , ( ). After ascending a height above the starting point direction of acceleration is reversed keeping its magntiude constant . Find time after start of motion of the car when clock will show the right time again .
Details And Assumptions-
a = 5 m/sec^2
g = 10 m/sec^2
h = 10 m .
give your answer is seconds
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the concept used is of the change in frequency of shm due to change in effective gravity !