Feasible Numbers

A natural number n n is called feasible if there exist non-negative integers a 1 , a 2 , . . . , a n a_{1},a_{2},...,a_{n} such that

1 2 a 1 + 1 2 a 2 + . . . + 1 2 a n = 1 3 a 1 + 2 3 a 2 + . . . + n 3 a n = 1 \frac{1}{2^{a_{1}}}+\frac{1}{2^{a_{2}}}+...+\frac{1}{2^{a_{n}}}=\frac{1}{3^{a_{1}}}+\frac{2}{3^{a_{2}}}+...+\frac{n}{3^{a_{n}}}=1

Find the number of feasible numbers n 997 n≤997


The answer is 499.

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