Fermat can solve this!

Algebra Level 4

n 6 − 9 n 5 + 33 n 4 − 62 n 3 + 66 n 2 − 36 n + 8 = m 3 n^{6}-9n^{5}+33n^{4}-62n^{3}+66n^{2}-36n+8=m^{3} find the sum of all possible value of n n such that m , n m,n is positive integer.


The answer is 3.

I Gede Arya Raditya Parameswara by I Gede Arya Raditya Para… , 17

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

[not complete solution]

n 3 + ( ( n − 1 ) ( n − 2 ) ) 3 = m 3 n^{3}+((n-1)(n-2))^{3}=m^{3} the possible value of n n is n = 0 n=0 or ( n − 1 ) ( n − 2 ) = 0 (n-1)(n-2)=0 and we done.

1 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...