Fermentation of glucose

Chemistry Level 3

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy from the formation of 1 1 mole of the compound from its constituent elements, with all substances in their standard states at 101.3 101.3 kPa and 298 298 K. The above shows the enthalpy change in formentation of glucose(C 6 _6 H 12 _{12} O 6 _6 ) to produce ethanol(C 2 _2 H 5 _5 OH). Which of the following statements is correct?

a) The standard heat of formation of C 6 _6 H 12 _{12} O 6 _6 ( s s ) ( Δ \Delta H) is 1260 -1260 kJ/mol.
b) The standard heat of formation of C 2 _2 H 5 _5 OH( l l ) ( Δ \Delta H) can be calculated from the above data.
c) The standard enthalpy of reaction( Δ \Delta H) when 1 1 mol of C 6 _6 H 12 _{12} O 6 _6 ( s s ) is fermented to produce C 2 _2 H 5 _5 OH( l l ) and CO 2 _2 ( g g ) is 82 82 kJ.

c) b) a) and b) a)

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1 solution

Lu Chee Ket
Jan 30, 2016

The standard starts from 6 C ( s ) + 6 H 2 ( g ) + 3 O 2 ( g ) ~\underline{6 C (s) + 6 H_2 (g) + 3 O_2 (g)} .

a) Heat released and therefore Δ H < 0 \Delta H < 0 .

b) From the standard, Δ H = 1342 k J / m o l \Delta H = - 1342 kJ/ mol is obtained from data instead of calculation.

c) 1 mole required Δ H = 82 k J \Delta H = - 82 kJ instead of 82 k J 82 kJ .

Answer: a ) \boxed{a)}

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