Ferris Wheel part 1

A Ferris wheel with radius r r is rotating at constant angular speed ω \omega . The position of a passenger at the rim of the wheel may be described by a direction angle θ \theta :

  • θ = 0 \theta = 0^\circ at the right side of the wheel

  • θ = 9 0 \theta = -90^\circ at the bottom of the wheel

  • θ = + 9 0 \theta = +90^\circ at the top of the wheel

Each passengers sits on a level (horizontal) seat. To prevent sliding off, the passenger can push on a bar for additional support. We call the force exerted by the bar on the passenger the "support force". In this problem we assume that this support force is purely horizontal.

Which of the equations correctly describes the support force on the passenger?

F / m = ω 2 r cos θ g sin θ F/m = \omega^2 r \cos \theta - g \sin \theta F / m = ω 2 r sin θ F/m = \omega^2 r \sin\theta F / m = ω 2 r cos θ F/m = \omega^2 r \cos\theta F / m = ω 2 r cos θ g F/m = \omega^2 r \cos \theta - g

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