Unnecessarily large fibonacci

How many Fibonacci numbers F n F_n divide F 100 F_{100} , where n n is a positive integer greater than 1?


The answer is 8.

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2 solutions

Discussions for this problem are now closed

Mehul Chaturvedi
Jan 25, 2015

Let F ( k ) F(k) be a k t h k^{th} fibonacci number then no. of factors of F ( k ) = F(k)= no. of factors of k k

Which gives us that no. of factors of F 100 F_{100} =No. of factors of 100 100

as 100 = 2 2 × 5 2 100=2^2 \times 5^2 \therefore no. of factors of 100 = ( 2 + 1 ) × ( 2 + 1 ) 9 100=(2+1)\times(2+1)\Rightarrow 9

hence our answer is 9 \Huge\Rightarrow\color{royalblue}{\boxed{9}}


For list of fibonacci nos. click here

The number of Fibonacci factors of F k F_{k} being equal to the number of factors of k k is a corollary of an even more interesting theorem that m n m | n iff F m F n F_{m} | F_{n} ! Nice problem Prashant Ramnani, although the number isn't that well chosen.

Jake Lai - 6 years, 4 months ago

The question is ill formed. The question asks for number of fibonacci numbers that divide 354...75 and not its number of factors.

Janardhanan Sivaramakrishnan - 6 years, 4 months ago

{1, 3, 5, 55, 6765, 75025, 12586269025, 354224848179261915075}

I found 8 only. I don't know which one that I missed out. I did this carefully. Anyone who is willing to do hard onto this question won't be wrong with information obtainable.

Lu Chee Ket - 6 years, 4 months ago

You are absolutely right. There are only eight distinct factors. F 100 F_{100} divides F i F_i for i = 1 , 2 , 4 , 5 , 10 , 20 , 25 , 50 , 100 i=1,2,4,5,10,20,25,50,100 . But, F 1 = F 2 = 1 F_1=F_2=1 . Hence, only 8 distinct factors.

Janardhanan Sivaramakrishnan - 6 years, 4 months ago

Exactly. Count the Fibonacci number 1 only once.

Lu Chee Ket - 6 years, 4 months ago
Rahul Saha
Jan 26, 2015

Use the well known fact that gcd ( F m , F n ) = F gcd ( m , n ) \gcd(F_m,F_n)=F_{\gcd(m,n)}

Let m = 100 m=100 . Then it is easy to see that n 100 n|100 .There are only 9 9 factors of 100 100 . Hence the answer is 9 9 .

Note that F 1 = F 2 = 1 F_1=F_2=1 . Hence, only 8 distinct factors.

Janardhanan Sivaramakrishnan - 6 years, 4 months ago

Correct.My solution is slightly wrong then.

Rahul Saha - 6 years, 3 months ago

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